Boosting Regulator Current for IC 78xx by MJ2955

Normally 78xx series ICs can be output currents for a maximum 1 A, or in the common usage, it is only up to 0.6A.
But we need more boost current up, how to do next?
In this increasing Regulator Current or circuit, the power transistor is used to provide most current to the load, to maintain a constant the voltage, by the little current still through the regulator IC intact.
Let’s say, I want a the 12V voltage regulator, and current output voltage at 5A, I must to use an IC No. 7812 and it can take a transistor number MJ2955 or TIP2955. The input voltage is enough I think that about 20V, which voltage drop across the transistor is approximately 8V. And it takes about 40Watt energy, which can be calculated = Vce * Ic. When is this. We need a cooling pad for Q1, which is large enough, it is very hot, may be cause damage.
If you want to add current to the IC 79xx or negative voltage, you can also easy to make, but simple NPN transistor type 2N3055 is only a number.

Boosting Regulator Current for IC 78xx by MJ2955

Increase the current IC LM7805

But this circuit not have protection over load
Sometimes we want to use. high current at a dc regulator 5v 3a. We can do this by using the voltage regulator IC1 positive constant number 7805.
The Q1-2N3792 and Q2-2N5956 of circuit will serve to increase current for IC regulator.The R2 acts as the anti-saturation of Q12N3792 and Q2-2N5956. Without R2 will allow the two transistors do not work.The output current can be from IC1 alone.R1 specify the bias current to IC1.And the current output of you against too much saturated with. The C1 functions in input power filter to smooth.And C2 serves to prevent interference with the pressure to pay out (Vout).

Increase the current IC LM7805

This circuit can help enlarge current of power supply circuit that use Ic regulator so well. you can use other IC 7805,7809,IC-7812,and IC7815.
Q1 is BFX88 or Equivalent
Q2 is BD132 or Equivalent

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