If you are looking for a good IR receiver circuit or infrared receiver projects. This post is one choice that should read. It is suitable for the Remote control and more circuit. Which you can do it in two ways: a simple version and the special infrared receiver circuit for you. Both circuits have a PCB layout: moreover, all parts you can buy them at a local store near you.
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Simple infrared receiverThis is a simple infrared receiver for the burglar alarm system or the other protection, etc. It uses a few components that there are most common transistors and photodiode receive an infrared signal. As Infrared Remote control transmitter by IC-555-BD137. Let’s build the Infrared receiver circuits. Which we have too many circuits. To begin with, the simple circuit as Figure 1. We will see that a photodiode connects in the reverse bias form. So, while the infrared light to hit it. It has very little current through it.
Figure 1 The simple Infrared receiver circuit But when the infrared light turn photodiode PD1. It will cause the current to flow through the diode is good. Next, it causes a voltage signal to the frequency of the signal transmitter set to transistor TR1(BC549). Which it connect with TR2(BC557) that is in an amplifier circuit with gain about 1000 times. Both capacitors C2 and C3 are the high pass filter circuit. While both diodes D2 and D3(1N4148) acts as the convert AC voltage signal to DCV. By has C5 will filter current to smooth. Last, The voltage output drive transistor TR3 to the relay works. The relay so work when has the infrared light from the transmission to the receiver. If the beam is cut or obscured. The relay will stop working. This circuit is suitable for use in the burglar alarm system or the other protection, etc.
Build Simple IR receiver circuitWe should make PCB layout as Figure 2 due to the high-frequency receiver from photodiode as low current. So was very disturbing. Figure 2 the PCB layout and components layout of simple infrared receiver The component list Q1____BC549____45V 100mA NPN Transistor Q2____BC557____45V 100mA PNP Transistor RY1___Relay 12V coil D1,D2____1N4148____75V 150mA Diodes D6___Photodiode D5,D6__1N4001____1A 50V Diodes C1____0.022uF 50V Ceramic capacitors C2____100uF 25V electrolytic capacitors C3____0.01uF 50V Ceramic capacitors C6____2.2uF 25V electrolytic capacitors C7____470uF 25V electrolytic capacitors R1____22K 1/4W Resistors R2____1.8M__________” R3____6.8K________” R4____1K__________” R5____1M__________” R6___4.7K_________”
Simple remote control tester circuitI am going to show you a simple remote control tester circuit. When the remote control is broken. We cannot use it. First, we should check the battery. If the battery is good. The remote circuit may be a problem. We cannot check it with a normal tool, multimeter. This simple remote control tester circuit may help you. It can read an infrared light of remote control.
How it worksThis circuit acts like the infrared receiver of electrical appliances. Because the human eye cannot see infrared light. But a phototransistor can detect infrared light. In this Simple remote control tester circuit. So we use the phototransistor as the light receiver from the remote control. If it is good. The phototransistor-Q1 will get the infrared light, the current flows through it to the base of Q2(PNP transistor BC558). It switches on. the current from the ground can flow through R1 to Q1. The Q1(PNP transistor) also gets a bias current. It is working. So LED1 lights up. Because a high current passes it. The variable resistor VR1 is used to adjust the sensitivity of the circuit. Related of Simple Remote Control circuits
- IR appliance switch circuit using any infra-red remote control
- Infrared Remote control 50 feet 2 Channel
- Small RF universal remote controls
How to build this projectIf you want to make this project. First, you may test them on a breadboard. So easy to make.
Parts you will need0.25W Resistors, tolerance: 5% R1: 10K R2: 470Ω R3: 1M VR1: 100K Potentiometer Semiconductors and others: Q1,Q2: BC558, 45V 0.1A, PNP TO-92 Transistor Q3: EP103, Phototransistor 9V battery When you like it. You can assemble them into Universal Board as Figure 2 —the components layout—. Figure 2 the components layout on universal PCB.
- Coaxial cable tester circuit
- Simple Continuity Tester circuit using IC-4011
- The Op-amp IC tester circuit
Special Infrared receiver using LM1458 CD40103As This simple projects, If you want the circuit with special features, can set the program to the circuit works. When you enter the input pulse signal of 1-256 time. Consider the circuits Infra Red Receiver for a larger version as described below. The special infrared receiver circuit. This contains 4 main parts of the work as follows: the signal receiver and filter circuit, the set waveform, the frequency divider and the driver relay circuit. The receiver signal and filter circuit. The component is received a signal is a photodiode D1, the signal that across D1 will be sent to the filter circuit that will allow the 5KHz frequency only can through it. Which consist of the feedback circuit R4, R5, and C2 that join with IC1. The determining circuit will cause a low frequency, this circuit has the gain equal to 1. But that frequency of 5 kHz will have the high gain as of 1,000 times. The 5Khz signal will be inserted to the double DC to DC converter include of D2,D3,R6,C4. Figure 2 The special infrared receiver circuit
Setting IR receiver waveformSince the waveform that may be inappropriate. We must set a new wave, which it has a range of up and down change quickly. Then, the setting circuits consist of a wave which is compared to IC1B. Input voltage with a defined voltage at Pin 2. will set a high output. But if the voltage lower than pin 2 then the voltage output is “0” This setting causes the noise signal that may be unusual to be eliminated. The LED-D4 is LED display of circuit. we know that the signal from the sender is entered the receiver to complete. Then, the IC2-CD4093 will set the waveform. Which IC2A and IC2B is the Schmitt trigger form. And the IC2C act as an inverter circuit. After that, the signal flow to the frequency divider-IC3-CD40103 The frequency divider circuit The frequency divider circuit works by using the divided frequency IC as a program types From the 2-256 number with setting the voltage at the control input pin. Which has 8 pin is the pin 4,5,6,7,10,11,12,13. The program is a binary base 2 by 1 = positive, 0 = ground. For LED-D5 show the working of the output pulse from the frequency divider circuit. Last, the output as above will flow to the transistor TR1 to the driver the relay to works as desired.
Build Special IR receiver circuitFirst of all, We can assemble all components of circuits onto the PCB. When you are sure all the wires and components are installed correctly. Next, experimental enter the DC power 9 volts to the receiver. It has scope hold at pin 3 of IC will see is the frequency bands 5Khz. But if there is no scope to capture the notice of the diodes will feel warm. After that, to connect the voltage to set the receiver signal to the photodiode LED D4, adjust VR1 until full brightness. Which normal is in the center. In general, we can use this receiver in a range of about 3.5 M. However, you want more than this far. You may use a combined optical blade. In addition, the photodiode should be in a sealed box, allowing only the aperture only. To avoid the signal of natural light. Setting counts number As above that, Setting counts possible input voltage at input pin counts to a decimal number by 2. Also the infrared circuit
- Infrared Remote control 50 feet 2 Channel
- DIY infrared remote extender circuits
- Infrared Remote control transmitters
- The cheap fire alarm circuit using infrared
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