This is 12 to 24 volt DC converter circuit, can step up voltage from 12V to 24V but current down. We have two circuits high current output about 1A to 2A ,that easy to builds and cheap. We will show you 2 circuits below.
Note: Also this you can see these: 12V to 40V DC converter
1. DC/DC Converter DC12V to 24V 2A by IC 40106 and Mosfet BUZ11
This is Circuit DC to DC Converter.
For input DC12V-24V 4A to Output 24V-48V 2A (inputX2) Use easy circuit simple part IC Digital Cmos : 40106 and Mosfet BUZ1.
If you have power supply source about 12V, from battery 4A sizes. But want to enhance voltage be 24V or about 2 times. This circuit has can to help you by it has prominent easy good point. It use the integrated circuit digital number CD4093 perform produce the frequency drive current change CD40106 bilateral the group trips work. By drive high current with power mosfet BUZ11 make output current collect at capacitors the very total up voltage bilateral the group then is double of Input power supply. or It can enhance voltage double , be 2 times there.
Detail to See Circuit.
Source: CEW circuit Electronics Book
2. DC to DC step up converter using TDA2004 or TDA2005
We can increase the DC voltage from 6 volts to 12 volts. Or from 12 volts to 24 volts with a simple model of The DC to DC step up converter circuit with use TDA2005 or TDA2004 as main.
This circuit is similar to Simple DC to DC step up converter using TDA2822. We use an IC amplifier features the original, is producing a high current frequency to store a voltage in the Capacitor is about 2 times the input. This circuit is not necessarily the coil and the device easily.
The working principle
As soon as, We feed the input pin 10 of IC1 (output of IC1/1) It starts with high voltage up. This voltage will get from charging of capacitor-C5 through diode-D1 cause have voltage increased about 2-fold.
Circuit diagram of DC to DC step up converter using TDA2004
The power supply has a current flowing through D2 and C6, Until the pin 10 of IC1 / 1 has a nearly zero. But at output of circuit will have voltage equals the input power supply.
At this point, pin 8 of IC1 (output of IC1 / 2) So begin have thec voltage rise instead. Because C5 stopped charging current. The capacitor-C7 so charged instead by through the input power supply. So the current flows to the D3 and C6, the voltage at pin 8 so drop near zero.
And the working of circuit will return to the first time. And when current out of pin 8 and pin 10 to Converge together at C6, cause output have voltage rises up one times. Which is equal to input together.
The capacitors C1-C4 acts as square wave generator about 5 Khz. To determined working of IC1.
Building,Testing and Application
When we are fully equipped and built PCB as Figure below and then soldering equipment, as Figure.
After examining the faulty circuit. Then test them with 12V battery at input and measure voltage ouput will have about 22V please watch as video below.
If you have 6 volts input, it can increase the output voltage is 12 volts, or feed input is 12 volts will have output is 24 volts Or nearby. Really the input entered from 5 volts to 12 volts. The output is then multiplied with the two input will be the output, or about 10 volts to 24 volts.
Parts you need.
Resistors 0.25 watts
Non polar capacitors such as Ceramic, Mylar , polyester.
C1, C3________0.0047uF 50V
C2, C4________0.022uF 50V
C8, C9, C10____0.1uF 50V
C5, C7________2200uF 25V
LED__________5mm color as you like.
Others part, PCB,Heatsink, etc.