The Fuse failure alarm with 2 led light that LED display when the load is low resistance or short circuit, fuse blow once. LED1,LED2 show fuse state. In circuit use a few parts.
How it works
This circuit will show the performance of the equipment,or Check the fuse in the circuit.The circuit is small and the power supply voltage of all kinds.
It display with LED, 2-color in one. Which is cathode common kind,the anode has two separate terminals.
If the circuit is functioning properly LED, it shown in green colour.
The display is red, when the fuse in the circuit is damaged.The resistor R1 limits the current to flow through the LED is about 2 mA.
This is enough to make the LED light.If it lowers the R1 down, the LED lights up.
In the normal operation of the circuit and The fuse is not damaged. The zener diode to prevent the green and red LED lights up simultaneously.
Zener diode prevents the LED is green and red lights simultaneously.
The high efficiency LED when connected in parallel. The red LED uses high-voltage so that only green LED lights up only.
Diodes D3 and D4 will prevent dangerous for the LED. While the half cycle negative voltage of the alternating current voltage.
However, if the DC supply voltage. I do not have to use diode protection.
How to build this projects
This project uses a few components so can assemble the circuits into the universal PCB board.
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Blown Fuse indicator circuit with LED Display
The components Lists.
LED1,LED2: LED as you want.
D1,D3: 1N4007__1A 1000V Diode
D2: 5.1V 0.5W
R1: 120K 0.5W resistors.
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