TIP3055 | Electronic Project Circuits

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65W Amplifier Class AB by LF351 ,TIP3055 and TIP2955

I like mini power amplifier less 100W because it is low cost nad easy to make project.
The 65W Amplifier Class AB,I use main part electronics are IC LF351 and thansisror two part TIP3055 and TIP2955.
The LF351 is a low cost high speed JFET input operational amplifier.
The TIP3055 and TIP2955 are small size but have high power.
This is circuit want Voltage supply +38V and -38V at current 3A min.
Have output power 65W to 75W at 8ohm speakers.

Be the first to comment - What do you think? Posted by admin - May 29, 2008 at 6:53 pm

Categories: Power Amplifier Tags: Class AB Amplifier, TIP2955, TIP3055

30W Class AB amplifier by TIP2955 + TIP3055

To set the above amplifier up, set R1 to max and R12 to 0. After doing this successfully, power on the amplifier. Set R1 so that the measured output offset is between 30 and 100mV. Once set, adjust R12 slowly to achieve a quiescent current of around 120mA. Keep checking the quiescent current as the amp heats up as it might change due to voltage drop changes in the output devices caused by heat. The heatsinks should be 0.6K/W or less for two amplifiers.

Be the first to comment - What do you think? Posted by admin - February 13, 2008 at 4:40 pm

Categories: Power Amplifier Tags: 30 watt amplifier, Class AB Amplifier, TIP2955, TIP3055

A Simple Voltage Regulator +22V -22V by TIP3055,TIP2955

The TIP2955/TIP3055 transistors should be satisfactory for a power supply feeding a single amplifier. If two amplifiers are to be fed from a single power supply, these transistors should be changed to higher power devices such as the MJ2955/2N3055. Adequate heat-sinking must be provided for whichever transistors are used.

R9 and R10 can be replaced with a 10k preset potentiometer (or a 5k potentiometer in series with a 5k6 fixed resistor) to provide adjustment of the output voltage.

As with the capacitance multiplier circuit, Q2 and Q4 can be changed to a complimentary feedback pair arrangement, if required, to allow the use 2N3055s as the pass device in both halves of the supply (see the capacitance multiplier page for details). If this done, R9 and R10 must be made variable to allow the supply rails to be set to equal (but opposite) voltages.

Zener diodes of a different voltage rating can be used for ZD1 and ZD2, but the value of R9 and R10 will need to be adjusted to maintain the +/-22V output.

For different output voltages or a different Zener diode voltage, the output voltage can be calculated from the following equations:

+VOUT = ((R7 + R9) / R9) * (VZ + 0.6)

â€“VOUT = ((R8 + R10) / R10) * (VZ + 0.6)

where +VOUT and VOUT are the required supply rail voltages and VZ is the Zener voltage.

Read More Source:http://www.tcaas.btinternet.co.uk/jlhvoltreg.htm
Thank you.