Protection Power Supply | Electronic Project Circuits

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Fuse electronic for ic regulator

Power supply, plus the ground, using current up to 1 Amp.Normally used, IC Regulator no. 78XX. When used to power circuits.And the short circuit that occurred.If no fuse various equipment will be damaged.But if there is an electronic fuse circuit for IC number 78XX.Then when the, short-circuit.This circuit will act to stop paying current and voltage immediately.Thus preventing the loss.
When entering the input voltage, the circuit Q1 and Q2 at the circuit, a bi stable multivibrator circuit.The Q1 Q2 will start but will not work.Because, C1 connected to the base pin of Q1.Then, the charging.Therefore, the voltage at Pin Collector ‘s Q1, to bias the base pin of Q3.Through R4, so the Q3 conduct. And Q4 will conduct with.As a result, voltage input to pin 1 of IC1.Cause the output voltage Implemented.If there is a short circuit when? D1 has served as a ground to stand Q2 base pressure of about 0.3 volts, resulting in a loss Q2 stopped. Bi stable circuit has changed the operating environment to run Q1.
Making Q3, Q4 and IC78XX not work. There is no voltage at the output of the circuit.If you want to IC1 output voltage again, switch S1. To reset the circuit to return to work.Or the bi stable multibrator circuit changes state to work again, sure enough Q4 work.

Be the first to comment - What do you think? Posted by admin - November 16, 2010 at 4:33 am

Categories: Power supply, Security Tags: electronic fuse circuit, ic regulator protection, protection power supply

Blown Fuse indicator LED Display

A Fuse be the equipment protects that use often most. Because of cheapness can use protect electronics expensive circuit. Generally when fuse torn us can know immediately. but in sometimes Fuse torn already we don’t know. such as in electricity automobile system brake system , the system delays the electric current very much, etc. Fuse torn get into trouble at we must know for immediately the safety. I then beg for to advise the circuit is simple. It is can show with , LED that now. Fuse torn already please. See the illustration by equipment value that show that note for Voltage Source 12V , but if friends want to apply to the level Volt the other. As a result change value R1 and R2 get by can calculate from R1 = (Vin – 2) x 50 and R2 = (Vin – 2) x 10000/2 . Think the work of the circuit has a little, It may help to give friends comfortably go up please sir.