Generating -5 Volts From a 9 Volt Battery With IC 555


Generating -5 Volts From a 9 Volt Battery With IC 555

A 555 timer can be used to generate a squarewave to produce a negative voltage relative to the negative battery terminal. When the timer output at pin 3 goes positive, the series 22 uF capacitor charges through the diode (D1) to about 8 volts. When the output switches to ground, the 22 uF cap discharges through the second diode (D2) and charges the 100 uF capacitor to a negative voltage. The negative voltage can rise over several cycles to about -7 volts but is limited by the 5.1 volt zener diode which serves as a regulator. Circuit draws about 6 milliamps from the battery without the zener diode connected and about 18 milliamps connected. Output current available for the load is about 12 milliamps. An additional 5.1 volt zener and 330 ohm resistor could be used to regulate the +9 down to +5 at 12 mA if a symmetrical +/- 5 volt supply is needed. The battery drain would then be around 30 mA.

Source:http://ourworld.compuserve.com/homepages/Bill_Bowden/page10.htm#5volts.gif

Related Links
All circuits of 555 DC converter
All circuits of Negative Voltage DC Converter
All circuits of Positive to negative voltage
All circuits of Switching power supply 5V

9V battery changed to -5V
+9V and -9V from one 9V battery by MAX1044
5VDC to +12V and -12V Isolated dual Switching Regulator with LM2587
MC33167T switching regulator 5V 5A/-5V ,12V /-12V
-12V to -5V/400mA Regulator Ensures Sequencing With 5V Rail
MC33167T switching regulator 5V 5A/-5V ,12V /-12V


This entry was posted on Saturday, September 1st, 2007 at 10:53 pm and is filed under 555, dc converter, switching power supply.